You didn't say if the surface area included the base.
If it does:
πr^2 + πrs = 168π
divide by π
r^2 + 22r - 168 = 0
completing the square
r^2 + 22r + 121 = 168 + 121 = 289
(r+11)^2 = √289
r+11 = 17
r = 6
If you did not include the base,
πrs = 168π
22r = 168
r = 168/22 = 84/11
How do I find the radius of a right cone with a slant of 22 and surface area of 168pi m^2?
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