How do I find the magnitude from this data:
theta_1 = 44.9 theta_2 = 146.1
A = 4.8 cm B = 8.7 cm
6 answers
of vector (A + B)
I don't know where theta 1 and theta 2 are, but have you considered drawing the figure, then using the law of sines?
theta one goes with A and theta two goes with B. I know I'm supposed to use |A+B| =sqrt[ (A+B)x^2 + (A+B)y^2 ], but I am having troubles on which numbers I have to plug in for each value.
assuming the θ values are with respect to the positive x-axis, then
A = 4.8 cos44.9 i + 4.8 sin 44.9 j = 3.40i + 3.39j
B = -7.22i + 4.85j
now just add 'em up and take ||
A = 4.8 cos44.9 i + 4.8 sin 44.9 j = 3.40i + 3.39j
B = -7.22i + 4.85j
now just add 'em up and take ||
I keep getting the wrong answer. I got 4.42, is that wrong?
(A+B)x = -3.82
(A+B)y = 8.24
14.6 + 67.9 = 82.5
so
9.08
(A+B)y = 8.24
14.6 + 67.9 = 82.5
so
9.08
0 answers