sin^2(x) and [sin(x)]^2 mean the same thing. They are not the same as sin(x^2).
The derivative of sin^2(x) is
2 sinx cosx = sin(2x)
Think of u(x) as sin x and use the chain rule df/dx = df/du * du/dx = 2u *sinx
How do I find the derivative of sin^2(x) or written as sin(x)^2?
2 answers
I was confusing it with sin(x^2). Thank you for clearing this up for me! I have to pay attention to those parenthesis on my exam!