how do i find the derivative of 16^(sinx)

Answer 1

y = 16^(sin x)
ln y = sin x * ln 16

1/y y' = ln 16 * cos(x)

y' = ln 16 * cos x * 16^(sin x)

In general, d/dx (e^u) = e^u du/dx

d/dx (a^u) = ln a * a^u du/dx