How do I find the derivative for the sqrt(sin(e^(x^3)*cos(x)))???
I know this is a combination of the chain rule and product rule. Please help!
5 answers
Nothing?
You know, if no one responds right away, a better follow-up would be to show whatever ideas you have had in the meantime, rather than just tapping your foot and saying "nothing?".
Your first thought, on seeing a complicated formula should have been the chain rule. what functions u and v could you use?
y = √u where
u = sin(e^(x^3)*cos(x))
u = sin v
where v = e^(x^3)*cos(x)
Now you can work with things:
y' = 1/2√u u'
= 1/2√u cos v v'
Now use the product rule:
= 1/2√u cos v e^(x^3) (3x^2 cosx - x^3 sinx)
Now just substitute back in for u and v.
Your first thought, on seeing a complicated formula should have been the chain rule. what functions u and v could you use?
y = √u where
u = sin(e^(x^3)*cos(x))
u = sin v
where v = e^(x^3)*cos(x)
Now you can work with things:
y' = 1/2√u u'
= 1/2√u cos v v'
Now use the product rule:
= 1/2√u cos v e^(x^3) (3x^2 cosx - x^3 sinx)
Now just substitute back in for u and v.
Thanks for your response. I was hardly taping my foot. I have been working on this problem for almost 6 days and by the time I posted this, I was over it. So I apologize if it seemed like I was impatient.
You are the man!!!! I had tried this problem freaking 74 times. I had too many parenthesis, I forgot to add (e^(x^3)), and finally at the end of the derivative I did NOT include X^3 in front of sin(x).
Thank youuuuuuuu
Thank youuuuuuuu
Good work. Many many times it is easier to make a few simple substitutions to avoid all the punctuation. Even the most complex problems contain simple parts.
0 answers