w (9-w^2)
second factor is difference of squares
in general a^2-b^2 = (a-b)(a+b)
so
w (3-w)(3+w)
or
-w (w-3)(w+3)
How do I factor this, Please help me.9w-w^3
3 answers
Sorry Damon, I thought I was overlooked..I appreciate the help Thank you!!!
You are welcome.