D^2 = 1^2 + x^2
2D(dD/dt) = 2x(dx/dt)
when D = 6
36 = 1 + x^2
x=√35
dD/dt = 2(6)510)/(2(√35))
= 517.23 mi/h
How do I do this related rates problem?
A plane flying horizontally at an altitude of 1 mi and a speed of 510 mi/h passes directly over a radar station. Find the rate at which the distance from the plane to the station is increasing when it is 6 mi away from the station. (Round to the nearest whole number.)
2 answers
this is wrong you solved for the wrong side you need to solve for the hypotenuse. 6 is not the hypotenuse its a side. so the actual is sqrt(37).