How do I determine the value of the reaction
2HI(g) + 2.4 kcal --> H2(g) + i2(g)
delta H =
a) 2.4 kcal
b) -2.4 kcal
c) 0.00024 kcal
d) -0.00024 kcal
2HI(g) + 2.4 kcal --> H2(g) + i2(g)
delta H =
a) 2.4 kcal
b) -2.4 kcal
c) 0.00024 kcal
d) -0.00024 kcal
1 answer
1 answer
1 answer
1 answer