how do I calculate the mass of ammonium sulfate formed from the complete reaction of 700 grams of ammonia?

Answer 1

(NH4)2 SO4

how many moles of NH3 is in 700 grams. Figure that.

Now,in ammonium sulfate figure it like this (NH3 + H)2SO4. Put that number of moles you figured of NH3, and half that is the moles of ammonium sulfate. What mass is that?

mass=1/2 numbermolesNH3*molmass(NH4)2SO4