how do i balance the following(fill in the blanks):

Question

1.) __BF3 + __Li2SO3 --> __B2(SO3)3 + __LiF

2.) __CaCO3 + __H3PO4 --> __Ca3(PO4)2 + __H2CO3

3.) __B2Br6 + __HNO3 --> __B(NO3)3 + __HBr

Answer 1

#1. 2,3,1,3 but check it to make sure.
The others. You need to learn to do these yourself. Tell us what you don't understand about the process and we can help you through it.

Answer 2

if i were to put 2 for the first blank does it go to the B and the F3?

if it does wouldn't that mean the first would be B2F6 and the last would be Li3F3, so the F would be unbalanced?

i don't get that part...

Answer 3

2BF3 + 3Li2SO3 --> B2(SO3)3 + 6LiF

I made a typo. I typed 2,3,1,3 and I SHOULD have typed 2,3,1 6.
In answer to your question, no. The first rule of balancing equations is that you may change ONLY the coefficients. You may NOT change the subscripts. Therefore, placing a 2 as a coefficient for BF3 (2BF3) means you multiply the B and the F by 2 which gives you 2 B atoms and 6 F atoms. And that balances with the B2(SO3(3 (2 B atoms there) and the 6LiF (6 F atoms there).

Answer 4

i think im still a little confused

would the next one #2 be 3, 2, 1, 3

Answer 5

absolutely perfect. Want to go for two straight?

Answer 6

ummm 1,6,2,6????

idk haha

Answer 7

B2Br6 + __HNO3 --> __B(NO3)3 + __HBr

You ALWAYS know if the equation is balanced BECAUSE you ALWAYS check it after finishing. That way you will know if you made an error. Let's check this one.
I'll put in your numbers.
B2Br6 + 6HNO3 ==> 2B(NO3)3 + 6HBr

I see 2 B on the left and 2 on the right.
I see 6 Br on the left and 6 on the right.
I see 6H on the left and 6 on the right.
I see 6 NO3^- on the left and 6 on the right.
Looks to me as if you scored again! Good work!

Answer 8

oh alright i get it thanks :)