The interval has width 2, so if there are n rectangles in the sum,
the width of each is 2/n
using right endpoints, xk = 1+(2/n)*k
n
lim ∑(1+(2/n)*k)(2/n)
n->∞ k=1
how do decentralize goverment reduce environmental degradation
3 answers
The interval has width 2, so if there are n rectangles in the sum,
the width of each is 2/n
using right endpoints, xk = 1+(2/n)*k
n
lim ∑(1+(2/n)*k)(2/n)
n->∞ k=1
the width of each is 2/n
using right endpoints, xk = 1+(2/n)*k
n
lim ∑(1+(2/n)*k)(2/n)
n->∞ k=1
The interval has width 2, so if there are n rectangles in the sum,
the width of each is 2/n
using right endpoints, xk = 1+(2/n)*k
n
lim ∑(1+(2/n)*k)(2/n)
n->∞ k=1
the width of each is 2/n
using right endpoints, xk = 1+(2/n)*k
n
lim ∑(1+(2/n)*k)(2/n)
n->∞ k=1