Question

How do areas of two parallelgrams compare when the dimensions of one are three times the demensions of the other?

Answer 1

let's take a rectangle for example. It has a width of 2 and a lengh of 3. You just take A=lw so the are is (2)(3)= 6
The one that is three times the other is 2(3) and 3(3) or 6 x 9 = 45. It is 9 times bigger. 45/6 = 9

Answer 2

Or you could just do the Algebra. A=lw would be A=(cm)(cm) = cm^2 or A=(m)(m) = m^2 if you had the dimensions be 2 times the first one it would be 4 times as big, since it was squared. 3 would be 9 times, 4 would be 16 times, and so on.