How could the following code be adapted for a baseball score keeping?

Question

1 def scoreUpdate(value):
2 # update the score value with the points earned
3 return(value + 6)
4 def bonus(value):
5 return(value + 1)
6 score = 6
7 score = scoreUpdate(score)
8 print("after update " + str(score))
9 score = bonus(score)
10 print("after bonus "+ str(score))

(1 point)
Responses

Replace 6 with 1 in line 3 and remove the bonus section.
Replace 6 with 1 in line 3 and remove the bonus section.

Replace the 1 with a 2 in line 5.
Replace the 1 with a 2 in line 5.

Change line 7 to call bonus instead.
Change line 7 to call bonus instead.

Change the 6 to a 1 in line 6.

Answer 1

To adapt the provided code for baseball score keeping, we need to consider the way scoring works in baseball. In baseball, players score runs, usually represented as single points, and scorekeeping doesn't typically involve bonus points as shown in the provided code.

Here's a breakdown of how to adjust the code:

1. Update line 3: In baseball, we usually increment the score by 1 for each run scored. So, we should replace 6 with 1 in line 3, since a run in baseball is worth one point.

2. Remove the bonus functionality: The bonus function isn't needed for baseball scorekeeping; the score only increases by runs scored.

3. Change initial score: The initial score in line 6 should start at 0 instead of 6 (if the teams begin with no scores).

Here’s the revised code reflecting these adjustments:

def scoreUpdate(value):
    # update the score value with the points earned
    return(value + 1)  # Change 6 to 1 for incrementing by 1 run

score = 0  # Change initial score from 6 to 0
score = scoreUpdate(score)
print("after update " + str(score))

In summary, the correct responses would be:

• Replace the 6 with a 1 in line 3.
• Remove the bonus section.
• Change the initial score from 6 to 0 in line 6.

Based on the options provided, the appropriate response to adapt the code as requested would be:

1. Replace 6 with 1 in line 3 and remove the bonus section.
2. Change the 6 to a 0 in line 6.