How can you prove that the equation of any circle with radius (r) and the center at the origin is x^2+y^2=36?
Please help!?!
3 answers
YOu cant. The equation you gave is for radius 6 only.
Sorry, I meant how can you prove that the equation of any circle with radius (r) and the center at the origin is x^2+y^2=r^2?
find the distance from any point on the circle to the origin.
The distance from any point x1,y1 to a point x2,y2 is
distance=sqrt ((x1-x2)^2+(y1-y2)^2)
if the distance from any point is constant, that curve is a circle with radius=distance.
The distance from any point x1,y1 to a point x2,y2 is
distance=sqrt ((x1-x2)^2+(y1-y2)^2)
if the distance from any point is constant, that curve is a circle with radius=distance.