how can you condense these

cos^3x* cos2x^2

cos^3x+ cos2x^2

cos^3x- cos2x^2

Thanks a lot :)

Similar Questions
  1. Solve the equation of the interval (0, 2pi)cosx=sinx I squared both sides to get :cos²x=sin²x Then using tri indentites I came
    1. answers icon 4 answers
  2. Solve identity,(1-sin2x)/cos2x = cos2x/(1+sin2x) I tried starting from the right side, RS: =(cos²x-sin²x)/(1+2sinxcosx)
    1. answers icon 3 answers
  3. how can you condense thesecos^3x* cos2x^2 cos^3x+ cos2x^2 cos^3x- cos2x^2 Thank you soo much
    1. answers icon 1 answer
  4. Find all solutions to the equation in the interval [0, 2pi)cos4x-cos2x=0 So,this is what i've done so far: cos4x-cos2x=0
    1. answers icon 1 answer
more similar questions