The answer is 2C2H6 + 7O2 ———- 4CO2 + 6H20.
"most important thing about balancing equations is balancing the odd atoms first such as carbon, C in this case
balance 2 C on right because there’s already 2 C on left
this gives CO2 -> 2C02
next u balance hydrogen, H on the right because there is 6 on the left by H2O -> 3H2O
always balance oxygen O the last/last few because it can be easily balanced due to the O2 on the right, O2 -> 5/2O2
overall equation would look like,
C2H6 + 5/2O2 -> 2CO2 + 3H2O
in order to remove the fraction, multiply the entire equation by 2
C2H6 + 5/2O2 -> 2CO2 + 3H2O x2"
Quoted from Sim Seemin on Quora.
How can you balance this equation?
C(2)H(6) + O(2) ---> CO(2) + H(2)O
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