How can we filter out numbers less than 2 in a number sequence to find prime numbers?(1 point)%0D%0AResponses%0D%0A%0D%0AWe can test numbers less than 2 by checking if it is divisible by 2.%0D%0AWe can test numbers less than 2 by checking if it is divisible by 2.%0D%0A%0D%0AOur code needs to throw an error if numbers less than 2 are given.%0D%0AOur code needs to throw an error if numbers less than 2 are given.%0D%0A%0D%0AWe can have a conditional check to filter out numbers less than 2.%0D%0AWe can have a conditional check to filter out numbers less than 2.%0D%0A%0D%0AWe can have a predefined list of all prime numbers and check if the given number is inside that list.

1 answer

We can have a conditional check to filter out numbers less than 2. This can be done by adding an if statement in our code that checks if the number is less than 2. If the number is less than 2, we can skip it and move to the next number. Here is an example code snippet:

```python
def find_prime_numbers(sequence):
prime_numbers = []
for number in sequence:
if number < 2:
continue
# additional checks for prime numbers...
prime_numbers.append(number)
return prime_numbers
```

In this code snippet, we have a function called `find_prime_numbers` that takes a sequence of numbers as input. Within the for loop, we have an if statement that checks if the current number is less than 2. If it is, we use the `continue` statement to skip the current iteration and move to the next number. This effectively filters out numbers less than 2 from further processing.