[2a³c-2a³b+2ab³-2b³c+2bc³-2ac³]
= [ 2a^3(c-b) + 2b^3(a-c) + 2c^3(b-a) ]
after that I went to Wolfram and got
-2(a-b)(a-c)(b-c)(a+b+c)
http://www.wolframalpha.com/input/?i=factor+2a%C2%B3c-2a%C2%B3b%2B2ab%C2%B3-2b%C2%B3c%2B2bc%C2%B3-2ac%C2%B3
How can I factor these
[2a³c-2a³b+2ab³-2b³c+2bc³-2ac³]
2 answers
I am more interested in the working.....I also found out that on wolframalpha
2 answers