Hookes law states that the force , F in a spring extended by length x is given by F=-Kx. According to Newton's second law F=ma, where m is the mass and a is the acceleration. Calculate the dimension of the spring constant k.

Answer 1

-K x = m a

-K ⋅ meters = kg ⋅ m/s^2 = Newtons

K = - N / m

the spring force increases linearly (directly proportional to the stretch)
... in the direction opposite the elongation (stretching)