To find the two other decimals that Holland could have used to make a sum of 2, we start with the information provided:
- One of the decimals is \( 0.34 \).
- We need to find two other decimals, say \( x \) and \( y \), such that
\[ 0.34 + x + y = 2. \]
To isolate \( x + y \), we can subtract \( 0.34 \) from both sides:
\[ x + y = 2 - 0.34. \]
Calculating the right side gives:
\[ 2 - 0.34 = 1.66. \]
Now we have the equation:
\[ x + y = 1.66. \]
This equation means that the sum of the two decimals \( x \) and \( y \) must equal \( 1.66 \).
Since there are infinitely many pairs of decimals that can satisfy this equation, we can choose specific values for \( x \) and \( y \). For example:
- We could let \( x = 1.00 \) and hence \( y = 1.66 - 1.00 = 0.66 \).
- Another pair could be \( x = 0.80 \) and \( y = 1.66 - 0.80 = 0.86 \).
Thus, two possible pairs of decimals that Holland could have used to make a sum of 2 are:
- \( x = 1.00 \) and \( y = 0.66 \)
- or \( x = 0.80 \) and \( y = 0.86 \).
In summary, any two decimals that add up to \( 1.66 \) alongside \( 0.34 \) will suffice.