Hitomi has a total of 30 red and blue bowling balls at her bowling alley. Each red ball weighs 8 lb. Each blue ball weighs 9 lb. If the total mass of the blue balls is 49 lb. heavier than the total mass of the red balls, how many red balls does she have?

Answer 1

24.56

Answer 2

Let x = # red balls and 30-x = # blue balls

9(30-x) = 8x + 49

Solve for x.

Answer 3

what i did was i did=
x= # of red balls
30-x= # of blue balls

9(30-x)= 8 x + 49
and you get 13 red balls

Answer 4

This is hard

Answer 5

I have nooo idea

Answer 6

First, I turned this into an equation:
9(30-x)=8x+49
30-x is the blue bowling balls, and x is the red bowling balls. Heres how I solved it:

equation:
9(30-x)=8x+49

rearrange the equation:
9(-x+30)=8x+49

get rid of the 270:
-9x+270=8x+49
-270 -270

get rid of the 8x:
-9x=8x-270
-8x -8x

divide by -17
-17= -270
/-17 /-17

solution:
x=13

Hope this helps!