History - Spenser, Wednesday, October 10, 2007 at 1:33pm

Find the center and radius of x^2 + y^2 - x + 2y - 3 = 0

2 answers

You are looking for the form

(x-h)^2 + (y-k)^2 = r^2

x^2 -x +y^2 + 2y - 3=0
so grouping by perfect squares...
(x^2 -x + 1/4) + (y^2+2y+1)= +3-1/4-1

you do the rest. If you need help, repost.
i don't understand....