To determine which of the labeled points is a viable solution for the inequality \( 25x + 15y \geq 200 \), we can substitute the coordinates of each point into the inequality and see if it holds true.
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For the point \( (10, 10) \): \[ 25(10) + 15(10) = 250 + 150 = 400 \] Since \( 400 \geq 200 \) is true, \( (10, 10) \) is a viable solution.
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For the point \( (2, 3) \): \[ 25(2) + 15(3) = 50 + 45 = 95 \] Since \( 95 \geq 200 \) is false, \( (2, 3) \) is not a viable solution.
Thus, the viable solution from the labeled points is (10, 10).