Hint for this assignment: Pay attention to the units of measure. You may have to convert from feet to miles in this assignment. You can use 1 mile = 5,280 feet for your conversions.

1. Many people know that the weight of an object varies on different planets, but did you know that the weight of an object on earth also varies according to the elevation of the object? In particular, the weight of an object follows this equation: , where C is a constant, and r is the distance that the object is from the center of the earth.

a. Solve the equation for r.

b. Suppose that an object is 30 pounds when it is at sea level. Find the value of C that makes the equation true. (Sea level is approximately 4,000 miles from the center of the earth.)

c. Use the value of C you found in the previous question to determine how much the object would weigh in

i. Death Valley (282 feet below sea level)

ii. The top of Mt McKinley (20,320 feet above sea level)

2. The equation gives the distance, D, in kilometers that a person can see to the horizon from a height, h, in meters.

a. Solve this equation for h.

b. Mount Evans in the Rocky Mountain National Park, is 4,375 meters in elevation. How far can you see to the horizon from the top of Mount Evans? Can you see Fort Collins (about 220 kilometers away)? Explain your answer.

1 answer

1a. equation is r^-2=w/c

2. equation is d=3.6sqrt(h)
I forgot to include the equation into the problems.