hill that has a 37.7 % grade is one that rises 37.7 m vertically for every 100.0 m of distance in the horizontal direction. At what angle is such a hill inclined above the horizontal?
2 answers
According to the question:the hill rises at 37.7m to the vertical [y-axis] and 100m to the horizontal[x-axis] in the process a right-angle triangle is obtain and an angle of 90 is also obtain. 90 is the angle inclined at the horizontal
Grade = 100%*sin A = 37.7%
sin A = 37.7%/100% = 0.377
A = 22.1o
To climb a hill, the angle of inclination must be less than 90o.
sin A = 37.7%/100% = 0.377
A = 22.1o
To climb a hill, the angle of inclination must be less than 90o.