Hii please help with tessstt!!

Use the image to answer the question.

A coordinate plane shows the x-axis and y-axis labeled, both ranging from negative 6 to 6 in increments of 1. Quadrants 1 to 4 are labeled. Quadrant 1 is labeled with left parenthesis positive sign comma positive sign right parenthesis. Quadrant 2 is labeled with left parenthesis negative sign comma positive sign right parenthesis. Quadrant 3 is labeled with left parenthesis negative sign comma negative sign right parenthesis. Quadrant 4 is labeled with left parenthesis positive sign comma negative sign right parenthesis.

What can be the value of x
so that the ordered pair (x, 13)
is located in Quadrant II?

(1 point)
Responses

0
0

13
13

−14
negative 14

9

9 answers

To determine a value of \( x \) so that the ordered pair \( (x, 13) \) is located in Quadrant II, we need to recall that in Quadrant II, the \( x \)-coordinate is negative and the \( y \)-coordinate is positive.

In the ordered pair \( (x, 13) \):

  • The \( y \)-coordinate is 13, which is positive, so that part meets the requirement for Quadrant II.
  • For the \( x \)-coordinate, it must be negative.

Now let's evaluate the provided options:

  1. 0: This is neither positive nor negative, so it does not meet the criteria.
  2. 13: This is positive, so it does not meet the criteria for Quadrant II.
  3. −14: This is negative, which meets the criteria.
  4. 9: This is positive, so it does not meet the criteria.

Therefore, the only value of \( x \) that places the ordered pair \( (x, 13) \) in Quadrant II is −14.

Which of the following pairs of points is a reflection of each other across the y
-axis?(1 point)
Responses

(8, 1)
and (1, 8)
Left Parenthesis 8 comma 1 Right Parenthesis and Left Parenthesis 1 comma 8 Right Parenthesis

(13, −11)
and (−13, −11)
Left Parenthesis 13 comma negative 11 Right Parenthesis and Left Parenthesis negative 13 comma negative 11 Right Parenthesis

(1, 17)
and (1, −17)
Left Parenthesis 1 comma 17 Right Parenthesis and Left Parenthesis 1 comma negative 17 Right Parenthesis

(−6, −10)
and (6, 10)

To determine which pairs of points are reflections of each other across the \( y \)-axis, we need to remember that the reflection of a point \( (x, y) \) across the \( y \)-axis is \( (-x, y) \).

Let's evaluate each pair of points:

  1. (8, 1) and (1, 8):

    • Reflection of \( (8, 1) \) would be \( (-8, 1) \).
    • This pair does not reflect each other across the \( y \)-axis.
  2. (13, −11) and (−13, −11):

    • Reflection of \( (13, -11) \) would be \( (-13, -11) \).
    • These points are reflections of each other across the \( y \)-axis.
  3. (1, 17) and (1, −17):

    • Neither of these points reflects across the \( y \)-axis. Their \( x \)-coordinates are the same, which means they are the same horizontal distance from the \( y \)-axis, but do not reflect each other.
  4. (−6, −10) and (6, 10):

    • The reflection of \( (-6, -10) \) would be \( (6, -10) \), not \( (6, 10) \).

So, the only pair of points that are reflections of each other across the \( y \)-axis is:

(13, −11) and (−13, −11).

Use the image to answer the question.

A coordinate plane shows the x- and y- axes ranging from negative 16 to 16 in increments of 2. The point left parenthesis 14 comma negative 15 right parenthesis is plotted on the plane.

The point (14, −15)
is reflected across both the x
- and y
-axes. What are the coordinates of the reflected point?

(1 point)
(
,
)

To find the coordinates of the point \( (14, -15) \) when it is reflected across both the \( x \)-axis and the \( y \)-axis, we can follow these steps:

  1. Reflect across the \( x \)-axis:

    • The reflection of a point \( (x, y) \) across the \( x \)-axis changes the \( y \)-coordinate to its negative.
    • Thus, the reflection of \( (14, -15) \) across the \( x \)-axis is \( (14, 15) \).
  2. Reflect across the \( y \)-axis:

    • The reflection of a point \( (x, y) \) across the \( y \)-axis changes the \( x \)-coordinate to its negative.
    • So, the reflection of \( (14, 15) \) across the \( y \)-axis is \( (-14, 15) \).

Therefore, the coordinates of the reflected point after reflections across both axes are \((-14, 15)\).

Use the image to answer the question.

A coordinate plane has an x-axis and y-axis both ranging from negative 7 to 7 in increments of 1. Points labeled with zoo animal names are plotted. Quadrant 1 is labeled with left parenthesis positive sign comma positive sign right parenthesis. Pandas and koalas are plotted in quadrant 1. Pandas is shown at 2 increments on the x-axis and 3 increments on the y-axis. Koalas is shown at 5 increments on the x-axis and 2 increments on the y-axis. Quadrant 2 is labeled with left parenthesis negative sign comma positive sign right parenthesis. Giraffes, lions, and rhinos are plotted in quadrant 2. Giraffes is shown at 5 increments on the x-axis and 2 increments on the y-axis. Lions is shown at 3 increments on the x-asix and 5 increments on the y-axis. Rhinos is shown at 1 increment on the x-axis and 1 increment on the y-axis. Quadrant 3 is labeled with left parenthesis negative sign comma negative sign right parenthesis. Apes and chimpanzees are plotted in Quadrant 3. Apes is shown at 5 increments on the x-axis and 2 increments on the y-axis. Chimpanzees is shown at 7 increments on the x-axis and 5 increments on the y-axis. Quadrant 4 is labeled with left parenthesis positive sign comma negative sign right parenthesis. Frogs, lizards, and snakes are plotted in quadrant 4. Frogs is shown at 1 increment on the x-axis and 4 increments on the y-axis. Lizards is shown at 1 increment on the x-axis and 6 increments on the y-axis. Snakes is shown at 6 increments on the x-axis and 2 increments on the y-axis.

Sana is at the zoo and wants to see the frogs. Where should she go?

(1 point)
Responses

(−4, 1)
left parenthesis negative 4 comma 1 right parenthesis

(4, 1)
left parenthesis 4 comma 1 right parenthesis

(1, 4)
left parenthesis 1 comma 4 right parenthesis

(1, −4)

To find where Sana should go to see the frogs, we need to locate the coordinates of the frogs based on the information provided.

The frogs are plotted in Quadrant IV, and their coordinates are given as \( (1, 4) \).

In this case, looking at the options provided:

  1. (−4, 1): This is not the location of the frogs.
  2. (4, 1): This is not the location of the frogs.
  3. (1, 4): This is the correct location of the frogs.
  4. (1, −4): This is not the location of the frogs.

Therefore, Sana should go to (1, 4) to see the frogs.

Use the image to answer the question.

A coordinate grid shows the x-axis ranging from negative 12 to 12 and the y-axis also ranging from negative 12 to 12. Points labeled with winter activities are plotted. Sledding is plotted at left parenthesis 2 comma 12 right parenthesis. Skiing is plotted at left parenthesis negative 8 comma negative 4 right parenthesis, and ice skating is plotted at left parenthesis 2 comma negative 4 right parenthesis.

Shahriyar is at a winter park with his family. They go sledding first, then ice skating, then skiing. What is the total distance traveled between these locations?

(1 point)
miles

To calculate the total distance traveled by Shahriyar as he moves between the three points (sledding, ice skating, and skiing), we will use the distance formula for points in a 2D coordinate plane. The distance formula between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:

\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]

The three points are:

  • Sledding: \((2, 12)\)
  • Ice Skating: \((2, -4)\)
  • Skiing: \((-8, -4)\)

Step 1: Distance from Sledding to Ice Skating

Using the points \((2, 12)\) and \((2, -4)\):

\[ d_1 = \sqrt{(2 - 2)^2 + (-4 - 12)^2} = \sqrt{0 + (-16)^2} = \sqrt{256} = 16 \text{ miles} \]

Step 2: Distance from Ice Skating to Skiing

Using the points \((2, -4)\) and \((-8, -4)\):

\[ d_2 = \sqrt{(-8 - 2)^2 + (-4 - (-4))^2} = \sqrt{(-10)^2 + 0} = \sqrt{100} = 10 \text{ miles} \]

Step 3: Total Distance Traveled

Now, we add both distances to find the total distance traveled:

\[ \text{Total Distance} = d_1 + d_2 = 16 + 10 = 26 \text{ miles} \]

Thus, the total distance traveled by Shahriyar is 26 miles.