To solve the expression \( \frac{4}{5} \div \frac{3}{5} \), we find how many times \( \frac{3}{5} \) (the distance from the front door to the living room) fits into \( \frac{4}{5} \) (the distance from the bathroom to the living room).
This fits the context of option B, where it compares the distances from the bathroom to the living room and from the front door to the living room.
Here’s the breakdown:
- The distance from the bathroom to the living room is \( \frac{4}{5} \) of a foot.
- The distance from the front door to the living room is \( \frac{3}{5} \) of a foot.
- The scenario asks how many times farther away the bathroom is compared to the front door, which we determine by dividing the two distances: \( \frac{4}{5} \div \frac{3}{5} = \frac{4}{3} \).
Therefore, the correct match for the given expression \( \frac{4}{5} \div \frac{3}{5} \) is:
B. Mr. Morris is making a blueprint of a new house. The distance from the bathroom to the living room is \( \frac{4}{5} \) of a foot. The distance from the front door to the living room is \( \frac{3}{5} \) of a foot. How many times farther away from the living room is the bathroom than the front door?