Hi! Would one of you please check my work? Thanks! ( I used significant digits, by the way)
A student throws a 5.00 kg steel shot directly upwards so that it leaves his hand when it is 2.00 m above the ground. If its velocity is 0.15 m/s when it leaves his hand, calculate:
1.The shot's potential energy in the student's hand before he throws it
* I got 98.1 J
2.The work done to accelerate it to 15.0 m/s
* I got 98.1 J
3. The kinetic energy when it leaves his hand
* I got 5.6 * 10^-2 J
4. The total mechanical energy of the shot
* I got 98.2 J
5. The height above his hand where it stops rising
* I got 0.00115 m
6. The height above the ground at that point
* I got 2.00115 m
7. The potential energy relative to the ground at that point
* I got 98.16 J
8. The kinetic energy just before it strikes the ground
*I got 98.16
9. The velocity with which it strikes the ground
* I got 6.3 m/s
7 answers
Will I not get a different answer if the velocity is different, like you suggested?
Thanks!
3. Correct
5. Correct
6. Correct.
7. Correct
8. Correct
9. Correct.
was unusually low; but I assumed that a
change in velocity would change the
answer but not the procedure.