NaOBr, the salt of a strong base (NaOH) and a weak acid (HOBr), ionizes in water as follows:
NaOBr(s) + H2O ==> NaOH + HBr and the net ionic equation is
OBr^- + HOH ==> HOBr + OH^-
Hi
What is the netionicequation for NaOBr disolving in watr?
Thanks!
4 answers
thank you
wait, if you have
"NaOBr(s) + H2O ==> NaOH + HBr and the net ionic equation is
OBr^- + HOH ==> HOBr + OH^- "
why doesn't this:
NaOBr(s) + H2O ==> NaOH + HBr
become this:
Na+ + OBr- + H2O ==> Na+ + OH- + H+ + Br-
which would become
OBr- + H2O ==> OH- + H+ + Br-
Is the (immediate) above equation the net ionic equation??
Thank you
"NaOBr(s) + H2O ==> NaOH + HBr and the net ionic equation is
OBr^- + HOH ==> HOBr + OH^- "
why doesn't this:
NaOBr(s) + H2O ==> NaOH + HBr
become this:
Na+ + OBr- + H2O ==> Na+ + OH- + H+ + Br-
which would become
OBr- + H2O ==> OH- + H+ + Br-
Is the (immediate) above equation the net ionic equation??
Thank you
It does; however, you asked for the NET ionic equation and not the ionic equation. If you use the ionic equation and cancel the ion common to both sides (the Na^+), the net ionic equation results.
In addition, I see I made a typo in the molecular equation. It is
NaOBr + HOH ==> NaOH + HOBr
Finally, no, what you wrote in the "immediate above" equation is not correct since it is based on the wrong molecular equation (because of my typo, I assume). I hope this rsponse makes sense.
In addition, I see I made a typo in the molecular equation. It is
NaOBr + HOH ==> NaOH + HOBr
Finally, no, what you wrote in the "immediate above" equation is not correct since it is based on the wrong molecular equation (because of my typo, I assume). I hope this rsponse makes sense.
2 answers