Asked by Xiumin
Hi! The question is really confusing to me. I can't sketch/visualize the problem. :(
From a given position an observer notes that the angle of elevation of a rock is 47 degrees. After walking 1000 feet towards the rock, up a slope of 32 degrees, he finds the angle of elevation to be 75 degrees. Find the vertical distance of the rock above each point of observation.
From a given position an observer notes that the angle of elevation of a rock is 47 degrees. After walking 1000 feet towards the rock, up a slope of 32 degrees, he finds the angle of elevation to be 75 degrees. Find the vertical distance of the rock above each point of observation.
Answers
Answered by
Steve
Label the two observation points A,B and the rock R.
Drop a vertical from R and draw horizontals from A,B to intersect it at M,N. So, AM and BN are horizontal lines.
Let RN intersect the slope at P.
Drop a vertical from B to intersect AM at C.
We want the distances RN and RM
RN/BN = tan 75°
RM/AM = tan 32°
AM = BN + 1000 cos47°
RM = RN + 1000 sin47°
That should get you started. Let us know how things go.
Drop a vertical from R and draw horizontals from A,B to intersect it at M,N. So, AM and BN are horizontal lines.
Let RN intersect the slope at P.
Drop a vertical from B to intersect AM at C.
We want the distances RN and RM
RN/BN = tan 75°
RM/AM = tan 32°
AM = BN + 1000 cos47°
RM = RN + 1000 sin47°
That should get you started. Let us know how things go.
Answered by
Xiumin
Oh, I forgot, we were supposed to use the Sine Law. Sorry :3
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