Label the two observation points A,B and the rock R.
Drop a vertical from R and draw horizontals from A,B to intersect it at M,N. So, AM and BN are horizontal lines.
Let RN intersect the slope at P.
Drop a vertical from B to intersect AM at C.
We want the distances RN and RM
RN/BN = tan 75°
RM/AM = tan 32°
AM = BN + 1000 cos47°
RM = RN + 1000 sin47°
That should get you started. Let us know how things go.
Hi! The question is really confusing to me. I can't sketch/visualize the problem. :(
From a given position an observer notes that the angle of elevation of a rock is 47 degrees. After walking 1000 feet towards the rock, up a slope of 32 degrees, he finds the angle of elevation to be 75 degrees. Find the vertical distance of the rock above each point of observation.
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Oh, I forgot, we were supposed to use the Sine Law. Sorry :3
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