Hi! Thank you very much-- I know this is a 2dimensional inelastic collision but i'm not sure how to solve--

Question

"The mass of a blue block is 20% greater than the mass of the green block. Before colliding, the blocks approach each ther with momenta of equal magnitudes and opposite directions, and the green block has an initial speed of 10 m/s. Find the speeds of the blocks after the collision if half the kinetic energy is lost during the collision" There is a picture illustrating the collision---the green block (G) is moving to the right along the x axis, the blue block (B) is moving to the left along the x axis;;after the collision, G is moving 30 degrees north of east, and B is moving 30 degrees south of west.

I know that since initial momenta are equal, (with G = mass of green block)

(G)(10 m/s) = (1.2 G)(V of blue block)
divide both sides by G
so I solved for V of blue block = 8.333 m/s

Since "half the kinetic energy is lost during the collision"
I think
KEi(G) + KE(ib) = 0.5[KEf(G) + KEf(B)]

But I DO NOT know how to do the in between steps---I'm not sure how to work with velocity components in this problem!

Please assist! Thank you very much!!