Bailey, Andrea, Danny, Riley, anabelle, holly, LILLY, zachary, I'm stumped -- or whoever!
To quote one of our very good math and science tutors: “You will find here at Jiskha that long series of questions, posted with no evidence of effort or thought by the person posting, will not be answered. We will gladly respond to your future questions in which your thoughts are included.”
Hi, please help! How do i do this?
differentiate (2ax^2 + bx)/(bx^3 - cx)
2 answers
Treat the function as the ratio
f(x) = u(x)/v(x)
and use the formula for the derivative of the ratio of two functions
df/dx = [v du/dx - u dv/dx ]/ v^2
The rest is easy.
f(x) = u(x)/v(x)
and use the formula for the derivative of the ratio of two functions
df/dx = [v du/dx - u dv/dx ]/ v^2
The rest is easy.