15 minutes is 1/4 hour. So, adding up the distances after x hours, we have
50x + 42(x - 1/4) = 120
hi, one question i have is for the following problem:"Two families meet at a park for a picnic. At the end of the day, they part ways. Family A leaves 15 mins after family B and travels east at an average speed of 42mph; while, family b travels west at an average speed of 50 mph. Both families have approximately 160 miles to travel.
Find time (in hours and minutes that it takes for them to be 120 apart." For my equation i have it set up 42x-630+50=120. Is this correct. I set up a table with
r t d and for family a my equation for distance was 42(x-15) and my equation for Family B distance was 50x and then i combined the two to end up with 92x-630=120
1 answer
1 answer