hi, just wondering on how i should approach differentiating: loge1/(3-x)^5

Question

can i differentiate it as loge(3-x)^5?

sorry i meant to write (3-x)^-5

Hmmmm.
You are haveing a brain seizure. Watch this:

Ln x^-a= - ln x^a= -a ln x

Amazing.

So loge1/(3-x)^5= -5 ln(3-x)

Check my thinking.