Asked by phoebe
hi! just needed help on an FRQ for ap calculus ab. let me know if you have any questions for me. I'm just really confused as far as what I am meant to do. If you could walk me through it that would be amazing. THANKS!!
A population is modeled by a function P that satisfies the logistic differential equation. dP/dt = P/5(1-(P/10)).
A. If P(0) = 3, what is lim (as t approaches infinity)P(t)?
B. If P(0) = 20, what is lim (as t approaches infinity)P(t)?
C. A different population is modeled by a function Y that satisfies the seperable differential equation:
dY/dt=(Y/5)(1-(t/10)). Find Y(t) if Y(0) =3.
D. For the function Y found in part (c), what is lim(as t approaches infinity) Y(t)?
A population is modeled by a function P that satisfies the logistic differential equation. dP/dt = P/5(1-(P/10)).
A. If P(0) = 3, what is lim (as t approaches infinity)P(t)?
B. If P(0) = 20, what is lim (as t approaches infinity)P(t)?
C. A different population is modeled by a function Y that satisfies the seperable differential equation:
dY/dt=(Y/5)(1-(t/10)). Find Y(t) if Y(0) =3.
D. For the function Y found in part (c), what is lim(as t approaches infinity) Y(t)?
Answers
Answered by
Steve
well, you should start out by solving the DE:
P = 10/(1+c*e^(-t/5))
(A) P(0) = 3, so
10/(1+c) = 3
c = 7/3
P(t) = 10/(1 + 7/3 e^-t/5)
Now it's clear that P->10
Now try the rest.
P = 10/(1+c*e^(-t/5))
(A) P(0) = 3, so
10/(1+c) = 3
c = 7/3
P(t) = 10/(1 + 7/3 e^-t/5)
Now it's clear that P->10
Now try the rest.
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