y = 2(x-3)^2
(y/2) = (x-3)^2
x-3 = sqrt(y/2)
x = sqrt(y/2) + 3 is the answer.
Was the "square root" shown as a radical sign with a 2 in front? I makes no sense to write sqrt(2y/2). That would be just sqrt(y)
Hi. Im trying to figure out how to solve an equation for x. The equation is y=2(x-3)^2. If I were to work this out, I would have come up with the answer x=sqrt y/2 +3 but the answer is actually x=sqrt 2y/2 +3. I can't work out where the extra 2 has come from.
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