Hi, Im trying to do my math corrections and I cannot figure out 3!. That was explained no where in my lessons. Can someone please explain the steps? I used my calculator and mathway.com but mathway.com makes me pay for the steps. Please help me:)
3 answers
What is the problem?
by definition n! = 1 x 2 x 3 x .... x n
so 3! = 1 x 2 x 3 = 6
n has to be a positive integer, with the special definition of 0! = 1
most "scientific" calculator have the n! function
on mine it is the 2nd function of 4 on the number pad,
check to see if you see n! anywhere
On mine, to get 8!, I would press:
8
2ndF
4
=
and it would give me 40320
check: 1x2x3x4x5x6x7x8 = 40320
so 3! = 1 x 2 x 3 = 6
n has to be a positive integer, with the special definition of 0! = 1
most "scientific" calculator have the n! function
on mine it is the 2nd function of 4 on the number pad,
check to see if you see n! anywhere
On mine, to get 8!, I would press:
8
2ndF
4
=
and it would give me 40320
check: 1x2x3x4x5x6x7x8 = 40320
ok thanks