universal gravitation equation
f = G M1 M2 / r^2
there is only a single force of attraction between the masses
... at the apple, the force is toward the pie ; and vice versa
Hi! I'm a bit lost on this homework question. The question states "In one hand you hold a 0.2kg apple, in the other hand you hold a 0.95kg Pie. They are separated by 0.75m, what is the force of gravity of the apple on the pie and what is the force of gravity of the pie on the apple."
Not sure how to go about solving this one.
3 answers
Hi,
I'm not fully sure either? I thought we could work on this together?
I think we have to use the Gravitation Force Equation F = GMm/r^2 *like Scott said above*^
F = (6.67e-11)(?)(?)/0.75^2 <--- That is all I have so far? What M's did you use in which place?
I'm not fully sure either? I thought we could work on this together?
I think we have to use the Gravitation Force Equation F = GMm/r^2 *like Scott said above*^
F = (6.67e-11)(?)(?)/0.75^2 <--- That is all I have so far? What M's did you use in which place?
Tell me if I am correct?
F = (6.67e-11)(0.95)(0.2)/0.75^2
= 2.2529778e-11
round
Final answer
F = 2.25e-11 N
F = (6.67e-11)(0.95)(0.2)/0.75^2
= 2.2529778e-11
round
Final answer
F = 2.25e-11 N