Hi, I posted yesterday with this lab question.
"Calculate the molar amounts of NaOH used in the reaction with the HCl solution and with the HC2H3O2.
I think I got the answer to that with the help that I received. I had 5 mL of HCl, and I was using .100 M NaOH, so I got 5x10-4 mol of NaOH for that one. now for #2...
"Calculate the molar concentration (molarity) of the HCl solution and the HC2H3O2 solution."
Would I divide the 5.0x10-3L and divide that from 5.0x10-4L?
L x M = mols
0.005 x 0.1M = 5x10^-4 mols NaOH.
That is the mols HCl, too.
L x M = mols HCl
Plug in L and mols and calculate M.
Thank you very much! :)
1 answer
Yes, you would divide the 5.0x10-3L by the 5.0x10-4L to calculate the molar concentration of the HCl solution and the HC2H3O2 solution. You can use the formula M = moles/L to calculate the molarity.
2 answers