Hi, I have to use algebra to find the coordinates of the point where two lines intersect, the first line passes through the points 4,3 and 10,0 and the second line is y=6.

Any ideas would be very much appreciated, many thanks

2 answers

Y = 6 is a horizontal line. The other one we have to figure out
slope = (0-3)/(10-4) = -3/6 = -1/2
so
y = -x/2 + b
0 = -5+b
b = 5
so
y = -x/2 + 5
where does hat hit y=6?
6 = -x/2 + 5
-x/2 = 1
x = -2
so
(-2,6)
BY the way:
Always sketch a graph.
Then this stuff gets easy.
Similar Questions
    1. answers icon 2 answers
  1. Please help!!!!!The points A,B,C,D have coordinates (3,3), (8,0), (-1,1), (-6,4) respectively. a) Find the gradients of the
    1. answers icon 1 answer
  2. Consider the function F(x)=k(x^2)+3a) If the tangent lines to the graph of F at (t,F(t)) and (-t,F(-t)) are perpendicular, find
    1. answers icon 1 answer
    1. answers icon 1 answer
more similar questions