Hi! I have a question

Question

Heres the problem:
3-2[6-(4y-1)]

I got -8y-11 but it wasn't right and I don't know what i did wrong help please!

Answer 1

3 - 2[6 - (4y - 1)]

Start with the polynomial inside the bracket. Distribute the negative 1.

= 3 - 2[6 - 4y - (-1)]
= 3 - 2[6 - 4y + 1]
= 3 - 2[7 - 4y]

Now distribute the -2

= 3 - 2(12) - 2(-4y)
= 3 - 24 + 8y
= 8y - 21

Answer 2

Okay I got you up to the "Distribute the -2 then im confused...where did you get the 12 in 3-2(12)-2(-4y)?

Answer 3

I think it was a typo:

it should be
= 3 - 2(7) -2(-4y)
= 3 - 14 + 8y
= 8y - 11

Answer 4

Okay great that makes more since thanks