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Hi, I am working on stoichiometry and limiting reactant problems. I have worked through examples in my book and I did them righ...Asked by Alexa
Hi,
I am working on stoichiometry and limiting reactant problems. I have worked through examples in my book and I did them right and can solve for the excess, however there is one problem in the book that has confused me. I don't understand why they identified the limiting reactant as the one they did.
Equation
S8+4Cl2------4S2Cl2
200g of sulfur reacts with 100g of chlorine, what mass of disulfur dichloride is produced?
100g Cl2 *1mol cl2/70.91gcl2=1.410 mol Cl2
200g S2*1mol S8/256.5gS8=0.7797 mol S8
Isn't Sulfur the limiting reactant??? My book says its chlorine but I don't see how that is possible since sulfur is smaller and the ratio shows that.
I am working on stoichiometry and limiting reactant problems. I have worked through examples in my book and I did them right and can solve for the excess, however there is one problem in the book that has confused me. I don't understand why they identified the limiting reactant as the one they did.
Equation
S8+4Cl2------4S2Cl2
200g of sulfur reacts with 100g of chlorine, what mass of disulfur dichloride is produced?
100g Cl2 *1mol cl2/70.91gcl2=1.410 mol Cl2
200g S2*1mol S8/256.5gS8=0.7797 mol S8
Isn't Sulfur the limiting reactant??? My book says its chlorine but I don't see how that is possible since sulfur is smaller and the ratio shows that.
Answers
Answered by
Steve
Since 1 mole of S8 reacts with 4 moles of Cl2,
.779 moles S8 will need 3.116 moles of Cl2, but you only have 1.410 moles
Clearly the Cl2 is lacking here.
.779 moles S8 will need 3.116 moles of Cl2, but you only have 1.410 moles
Clearly the Cl2 is lacking here.
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