Ask a New Question
Menu

Hi,how do I find both solutions of the equation cos0 = 0.35 between degrees 0 and 360?

Many thanks

3 answers

the cosine is positive in the I and IV quadrant

using the inverse cosine function on your calculator

Ø = 69.513°

so Ø is either 69.513° or (360-69.513)° or 290.487°
i hope this is not ou question? as this is the exam cheat
i hope this is not ou question? as this is the exam cheat ...... YOU
Similar Questions
  1. Solvez^5 =-1 with the solutions in polar form. I've solved the equation z^5 =1, which I have Letz=r(cosθ+isinθ).
    1. answers icon 1 answer
  2. R =(cos0 -sin0)(sin0 -cos0) State the matrix R for 0=120 degrees NB 0 represents theta
    1. answers icon 0 answers
  3. 1.)P(-15/17,-8/17) is found on the unit crcle. find sin0 and cos0.2.)solve: x=Arc tan(-sq root3). 3.)find sec0 if sin0=-4/5 and
    1. answers icon 1 answer
  4. Mulitple ChoiceFind cos0 if sin0=3/5 and 90 degrees<0<180 degrees. A.)4/5 B.)-4/5 C.)(Sq root 34)/5 D.)(- sq root 34)/5
    1. answers icon 1 answer
more similar questions