4Al + 3O2 ==> 2Al2O3
1.58 mols O atoms = 1.58/2 = 0.79 mols O2 molecules.
Use the coefficients to change from 0.79 mols O2 to mols Al.
That's 0.79 x (4 mols Al/3 mols O2) = 0.79 x 4/3 = ?
Hi guys. I cannot figure out how to do this question. Can you please do all the working out. Thanks
How many moles of Al atoms are needed to combine with 1.58 mol of O atoms to make aluminum oxide, Al2O3?
2 answers
0.26546666666...... I.e., 0.27