HI,

Question

Function: y=5cot(-2x)

can someone can please help me find the coordinates of the two halfway points of the principal cycles. Here are some answers that might help.

-I found the interval: (0,pi/2)
-The equation of the left vertical asymptote: x=0, and right asy: x=pi/2
-The coordinate of the center point of the principal cycle: (pi/4,0)

Now, I have to find the coordinate of the two halfway points of the principal cycle. I found the x coordinates of the question, which are(pi/6, ?),(pi/3,?). I'm trying to figure out the y coordinates. Please show step by step process + answer.

THANKS!

Answer 1

Excuse me?? Can you not just plug in the x-value?

y = 5cot(-2x)

so, at x = π/6,
y = 5cot(-2 * π/6)
= 5cot(-π/3)
= -5cot(π/3)
= -5/√3