There are no intervals involved.
since sin(π/4) = 1/√2
the principal value of arcsin,
Sin^-1(1/√2) = π/4
But, since there are many other angles,
sin^-1(1/√2) = π/4 or 3π/4
and since the period of sin(x) is 2π,
sin^-1(1/√2) = π/4 + 2nπ or 3π/4 + 2nπ
Or, since those values are in QI and QII, symmetric with the y-axis,
sin^-1(1/√2) = (4n+1)(π/2) ± π/4
Hi,
Find the exact value of the following expression:
Sin^-1(1/radical2)
(Its inverse sin(1/radical2)
Direction -(Type your answers in interval notation. Type an exact answer using pi as need)
Please show how you got the answers so I can use this as a reference for others. THANK YOU.
1 answer
1 answer