Area = x y
A = x (36 - x^2) = 36 x - x^3
domain is 0 </= x </= 6
assuming that it has to be on the POSITIVE x axis( the function would work fine for negative x but you specified + x)
for largest I have to use calculus
dA/dx = 0 at max = 36 -3 x^2
x^2 = 12
x = 2 sqrt 3 which is about 3.464
then
A = 36(3.464) - 3.464^3
= 83.1
Hi could you please help me with this algebra question.
A rectangle has one corner on the graph of y=36-x^2, another at the origin, a 3rd on the positive y-axis, and the fourth on the positive x-axis. Express the area A of the rectangle as a function of x. What is the domain of x? And what value of x is A largest?
1 answer