Hi! Could someone possibly help me solve this?; log2(x+4)=log2(x^2+2). For my answer, I got "All Real Numbers" or x=0 but I'm not sure if that's right. Thanks a bunch! :)

Answer 1

Log2(x+4) = Log2(x^2+2)
x + 4 = x^2 + 2
x - x^2 = 2 - 4
-x^2 + x = -2
-x^2 + x + 2 = 0
Multiply both sides by -1:
x^2 - x - 2 = 0
-2 = -2*1. Sum = -2 + 1 = -1 = B.

x+(-2)) = 0
x-2 = 0
X = 2

x+1 = 0
X = -1

Solution: X = -1, and 2.