Hi can someone solve this for me.2logy = log2 + 3logx, 2 ^ y = 4 ^ x

Answer 1

taking antilog ... y^2 = 2 x^3

2^y = (2^2)^x ... 2^y = 2^(2x) ... y = 2 x

substituting ... 4 x^2 = 2 x^3
... solve for x , then substitute back to find y