f= (1/x-.5)/(x-2)
as x>>2, (1/2=1/2)/(2-2) so it is of the form 0/0, so use LHopitals rule
as x>>2= (-1/x^2)/(1)= -1/4 / 1= -1/4
Hey, we covered limits at the beginning of the year, but I cannot remember how to do them at all.
>>>what is the limit, as x approaches 2, of ((1/x )-(1/2))/(x-2)?
Please go step by step!
1 answer
1 answer